12b+2+6=5(3b+1)

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Solution for 12b+2+6=5(3b+1) equation: 



12b+2+6=5(3b+1)

We move all terms to the left:

12b+2+6-(5(3b+1))=0

We add all the numbers together, and all the variables

12b-(5(3b+1))+8=0



We calculate terms in parentheses: -(5(3b+1)), so:

5(3b+1)

We multiply parentheses

15b+5

Back to the equation:

-(15b+5)



We get rid of parentheses

12b-15b-5+8=0

We add all the numbers together, and all the variables

-3b+3=0

We move all terms containing b to the left, all other terms to the right

-3b=-3

b=-3/-3

b=1

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