12b+6=128

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Solution for 12b+6=128 equation: 



12b+6=128

We move all terms to the left:

12b+6-(128)=0

We add all the numbers together, and all the variables

12b-122=0

We move all terms containing b to the left, all other terms to the right

12b=122

b=122/12

b=10+1/6

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