12b+8((b-4)/10)=348

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Solution for 12b+8((b-4)/10)=348 equation:



12b+8((b-4)/10)=348
We move all terms to the left:
12b+8((b-4)/10)-(348)=0
We multiply all the terms by the denominator
12b*10)+8((b-4)-348*10)=0
We add all the numbers together, and all the variables
12b*10)+8((b-4)=0
Wy multiply elements
120b^2=0
a = 120; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·120·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:
$b=\frac{-b}{2a}=\frac{0}{240}=0$

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