12c+-2(c+1)=8c+22

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Solution for 12c+-2(c+1)=8c+22 equation: 



12c+-2(c+1)=8c+22

We move all terms to the left:

12c+-2(c+1)-(8c+22)=0

We add all the numbers together, and all the variables

12c-2(c+1)-(8c+22)=0

We multiply parentheses

12c-2c-(8c+22)-2=0

We get rid of parentheses

12c-2c-8c-22-2=0

We add all the numbers together, and all the variables

2c-24=0

We move all terms containing c to the left, all other terms to the right

2c=24

c=24/2

c=12

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