12c+20=4+22c

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Solution for 12c+20=4+22c equation:



12c+20=4+22c
We move all terms to the left:
12c+20-(4+22c)=0
We add all the numbers together, and all the variables
12c-(22c+4)+20=0
We get rid of parentheses
12c-22c-4+20=0
We add all the numbers together, and all the variables
-10c+16=0
We move all terms containing c to the left, all other terms to the right
-10c=-16
c=-16/-10
c=1+3/5

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