12c+30=(c-5)

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Solution for 12c+30=(c-5) equation: 



12c+30=(c-5)

We move all terms to the left:

12c+30-((c-5))=0



We calculate terms in parentheses: -((c-5)), so:

(c-5)

We get rid of parentheses

c-5

Back to the equation:

-(c-5)



We get rid of parentheses

12c-c+5+30=0

We add all the numbers together, and all the variables

11c+35=0

We move all terms containing c to the left, all other terms to the right

11c=-35

c=-35/11

c=-3+2/11

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