12c+3c+75=9c+21

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Solution for 12c+3c+75=9c+21 equation: 



12c+3c+75=9c+21

We move all terms to the left:

12c+3c+75-(9c+21)=0

We add all the numbers together, and all the variables

15c-(9c+21)+75=0

We get rid of parentheses

15c-9c-21+75=0

We add all the numbers together, and all the variables

6c+54=0

We move all terms containing c to the left, all other terms to the right

6c=-54

c=-54/6

c=-9

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