12c-10=2(1+6c)

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Solution for 12c-10=2(1+6c) equation: 



12c-10=2(1+6c)

We move all terms to the left:

12c-10-(2(1+6c))=0

We add all the numbers together, and all the variables

12c-(2(6c+1))-10=0



We calculate terms in parentheses: -(2(6c+1)), so:

2(6c+1)

We multiply parentheses

12c+2

Back to the equation:

-(12c+2)



We get rid of parentheses

12c-12c-2-10=0

We add all the numbers together, and all the variables

-12!=0

There is no solution for this equation

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