12c-24=5(c+1)+4c+4

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Solution for 12c-24=5(c+1)+4c+4 equation: 



12c-24=5(c+1)+4c+4

We move all terms to the left:

12c-24-(5(c+1)+4c+4)=0



We calculate terms in parentheses: -(5(c+1)+4c+4), so:

5(c+1)+4c+4

We add all the numbers together, and all the variables

4c+5(c+1)+4

We multiply parentheses

4c+5c+5+4

We add all the numbers together, and all the variables

9c+9

Back to the equation:

-(9c+9)



We get rid of parentheses

12c-9c-9-24=0

We add all the numbers together, and all the variables

3c-33=0

We move all terms containing c to the left, all other terms to the right

3c=33

c=33/3

c=11

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