12c-6(c+2)=12

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Solution for 12c-6(c+2)=12 equation: 



12c-6(c+2)=12

We move all terms to the left:

12c-6(c+2)-(12)=0

We multiply parentheses

12c-6c-12-12=0

We add all the numbers together, and all the variables

6c-24=0

We move all terms containing c to the left, all other terms to the right

6c=24

c=24/6

c=4

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