12c-6c(c+2)=12

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Solution for 12c-6c(c+2)=12 equation: 



12c-6c(c+2)=12

We move all terms to the left:

12c-6c(c+2)-(12)=0

We multiply parentheses

-6c^2+12c-12c-12=0

We add all the numbers together, and all the variables

-6c^2-12=0

a = -6; b = 0; c = -12;
Δ = b2-4ac
Δ = 02-4·(-6)·(-12)
Δ = -288
Delta is less than zero, so there is no solution for the equation

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