12f+10=40-3f

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Solution for 12f+10=40-3f equation: 



12f+10=40-3f

We move all terms to the left:

12f+10-(40-3f)=0

We add all the numbers together, and all the variables

12f-(-3f+40)+10=0

We get rid of parentheses

12f+3f-40+10=0

We add all the numbers together, and all the variables

15f-30=0

We move all terms containing f to the left, all other terms to the right

15f=30

f=30/15

f=2

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