12g-6(g+1)=4(2g-1)-8

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Solution for 12g-6(g+1)=4(2g-1)-8 equation: 



12g-6(g+1)=4(2g-1)-8

We move all terms to the left:

12g-6(g+1)-(4(2g-1)-8)=0

We multiply parentheses

12g-6g-(4(2g-1)-8)-6=0



We calculate terms in parentheses: -(4(2g-1)-8), so:

4(2g-1)-8

We multiply parentheses

8g-4-8

We add all the numbers together, and all the variables

8g-12

Back to the equation:

-(8g-12)



We add all the numbers together, and all the variables

6g-(8g-12)-6=0

We get rid of parentheses

6g-8g+12-6=0

We add all the numbers together, and all the variables

-2g+6=0

We move all terms containing g to the left, all other terms to the right

-2g=-6

g=-6/-2

g=+3

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