12j+10j+18=-12+3j

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Solution for 12j+10j+18=-12+3j equation: 



12j+10j+18=-12+3j

We move all terms to the left:

12j+10j+18-(-12+3j)=0

We add all the numbers together, and all the variables

12j+10j-(3j-12)+18=0

We add all the numbers together, and all the variables

22j-(3j-12)+18=0

We get rid of parentheses

22j-3j+12+18=0

We add all the numbers together, and all the variables

19j+30=0

We move all terms containing j to the left, all other terms to the right

19j=-30

j=-30/19

j=-1+11/19

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