12j+6=2(3+6j)

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Solution for 12j+6=2(3+6j) equation: 



12j+6=2(3+6j)

We move all terms to the left:

12j+6-(2(3+6j))=0

We add all the numbers together, and all the variables

12j-(2(6j+3))+6=0



We calculate terms in parentheses: -(2(6j+3)), so:

2(6j+3)

We multiply parentheses

12j+6

Back to the equation:

-(12j+6)



We get rid of parentheses

12j-12j-6+6=0

We add all the numbers together, and all the variables

=0

j=0/1

j=0

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