12j-15=3(2j+3)

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Solution for 12j-15=3(2j+3) equation: 



12j-15=3(2j+3)

We move all terms to the left:

12j-15-(3(2j+3))=0



We calculate terms in parentheses: -(3(2j+3)), so:

3(2j+3)

We multiply parentheses

6j+9

Back to the equation:

-(6j+9)



We get rid of parentheses

12j-6j-9-15=0

We add all the numbers together, and all the variables

6j-24=0

We move all terms containing j to the left, all other terms to the right

6j=24

j=24/6

j=4

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