12j=16(I-8)

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Solution for 12j=16(I-8) equation: 



12j=16(-8)

We move all terms to the left:

12j-(16(-8))=0

We add all the numbers together, and all the variables

12j+128=0

We move all terms containing j to the left, all other terms to the right

12j=-128

j=-128/12

j=-10+2/3

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