12k+3(k+5)=48

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Solution for 12k+3(k+5)=48 equation: 



12k+3(k+5)=48

We move all terms to the left:

12k+3(k+5)-(48)=0

We multiply parentheses

12k+3k+15-48=0

We add all the numbers together, and all the variables

15k-33=0

We move all terms containing k to the left, all other terms to the right

15k=33

k=33/15

k=2+1/5

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