12m(m+2)=7m-6

Solution for 12m(m+2)=7m-6 equation:

12m(m+2)=7m-6

We move all terms to the left:

12m(m+2)-(7m-6)=0

We multiply parentheses

12m^2+24m-(7m-6)=0

We get rid of parentheses

12m^2+24m-7m+6=0

We add all the numbers together, and all the variables

12m^2+17m+6=0

a = 12; b = 17; c = +6;
Δ = b2-4ac
Δ = 172-4·12·6
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1}=1$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(17)-1}{2*12}=\frac{-18}{24}
=-3/4
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(17)+1}{2*12}=\frac{-16}{24}
=-2/3
$