12m+12=6(3m+3)-4m

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Solution for 12m+12=6(3m+3)-4m equation: 



12m+12=6(3m+3)-4m

We move all terms to the left:

12m+12-(6(3m+3)-4m)=0



We calculate terms in parentheses: -(6(3m+3)-4m), so:

6(3m+3)-4m

We add all the numbers together, and all the variables

-4m+6(3m+3)

We multiply parentheses

-4m+18m+18

We add all the numbers together, and all the variables

14m+18

Back to the equation:

-(14m+18)



We get rid of parentheses

12m-14m-18+12=0

We add all the numbers together, and all the variables

-2m-6=0

We move all terms containing m to the left, all other terms to the right

-2m=6

m=6/-2

m=-3

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