12m+3(m-1)=-2(m+1)+16

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Solution for 12m+3(m-1)=-2(m+1)+16 equation: 



12m+3(m-1)=-2(m+1)+16

We move all terms to the left:

12m+3(m-1)-(-2(m+1)+16)=0

We multiply parentheses

12m+3m-(-2(m+1)+16)-3=0



We calculate terms in parentheses: -(-2(m+1)+16), so:

-2(m+1)+16

We multiply parentheses

-2m-2+16

We add all the numbers together, and all the variables

-2m+14

Back to the equation:

-(-2m+14)



We add all the numbers together, and all the variables

15m-(-2m+14)-3=0

We get rid of parentheses

15m+2m-14-3=0

We add all the numbers together, and all the variables

17m-17=0

We move all terms containing m to the left, all other terms to the right

17m=17

m=17/17

m=1

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