12m+8-5+2+m=6(m+1)

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Solution for 12m+8-5+2+m=6(m+1) equation: 



12m+8-5+2+m=6(m+1)

We move all terms to the left:

12m+8-5+2+m-(6(m+1))=0

We add all the numbers together, and all the variables

13m-(6(m+1))+5=0



We calculate terms in parentheses: -(6(m+1)), so:

6(m+1)

We multiply parentheses

6m+6

Back to the equation:

-(6m+6)



We get rid of parentheses

13m-6m-6+5=0

We add all the numbers together, and all the variables

7m-1=0

We move all terms containing m to the left, all other terms to the right

7m=1

m=1/7

m=1/7

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