12n(n-1)=n(n+1)(n+2)

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Solution for 12n(n-1)=n(n+1)(n+2) equation: 



12n(n-1)=n(n+1)(n+2)

We move all terms to the left:

12n(n-1)-(n(n+1)(n+2))=0

We multiply parentheses

12n^2-12n-(n(n+1)(n+2))=0

We multiply parentheses ..

12n^2-(n(+n^2+2n+n+2))-12n=0



We calculate terms in parentheses: -(n(+n^2+2n+n+2)), so:

n(+n^2+2n+n+2)

We multiply parentheses

n^3+2n^2+n^2+2n

We do not support enpression: n^3

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