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12n(n-1)=n(n+1)(n+2)
We move all terms to the left:
12n(n-1)-(n(n+1)(n+2))=0
We multiply parentheses
12n^2-12n-(n(n+1)(n+2))=0
We multiply parentheses ..
12n^2-(n(+n^2+2n+n+2))-12n=0
We calculate terms in parentheses: -(n(+n^2+2n+n+2)), so:
n(+n^2+2n+n+2)
We multiply parentheses
n^3+2n^2+n^2+2n
We do not support enpression: n^3
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