12n+4(n+4)-4(n+1)=

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Solution for 12n+4(n+4)-4(n+1)= equation:


Simplifying
12n + 4(n + 4) + -4(n + 1) = 0

Reorder the terms:
12n + 4(4 + n) + -4(n + 1) = 0
12n + (4 * 4 + n * 4) + -4(n + 1) = 0
12n + (16 + 4n) + -4(n + 1) = 0

Reorder the terms:
12n + 16 + 4n + -4(1 + n) = 0
12n + 16 + 4n + (1 * -4 + n * -4) = 0
12n + 16 + 4n + (-4 + -4n) = 0

Reorder the terms:
16 + -4 + 12n + 4n + -4n = 0

Combine like terms: 16 + -4 = 12
12 + 12n + 4n + -4n = 0

Combine like terms: 12n + 4n = 16n
12 + 16n + -4n = 0

Combine like terms: 16n + -4n = 12n
12 + 12n = 0

Solving
12 + 12n = 0

Solving for variable 'n'.

Move all terms containing n to the left, all other terms to the right.

Add '-12' to each side of the equation.
12 + -12 + 12n = 0 + -12

Combine like terms: 12 + -12 = 0
0 + 12n = 0 + -12
12n = 0 + -12

Combine like terms: 0 + -12 = -12
12n = -12

Divide each side by '12'.
n = -1

Simplifying
n = -1

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