12n-10=2+(n-1)12

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Solution for 12n-10=2+(n-1)12 equation: 



12n-10=2+(n-1)12

We move all terms to the left:

12n-10-(2+(n-1)12)=0



We calculate terms in parentheses: -(2+(n-1)12), so:

2+(n-1)12

determiningTheFunctionDomain
(n-1)12+2

We multiply parentheses

12n-12+2

We add all the numbers together, and all the variables

12n-10

Back to the equation:

-(12n-10)



We get rid of parentheses

12n-12n+10-10=0

We add all the numbers together, and all the variables

=0

n=0/1

n=0

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