12n-3(3n-5)=25-2n

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Solution for 12n-3(3n-5)=25-2n equation: 



12n-3(3n-5)=25-2n

We move all terms to the left:

12n-3(3n-5)-(25-2n)=0

We add all the numbers together, and all the variables

12n-3(3n-5)-(-2n+25)=0

We multiply parentheses

12n-9n-(-2n+25)+15=0

We get rid of parentheses

12n-9n+2n-25+15=0

We add all the numbers together, and all the variables

5n-10=0

We move all terms containing n to the left, all other terms to the right

5n=10

n=10/5

n=2

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