If it's not what You are looking for type in the equation solver your own equation and let us solve it.
((2*x-1)*(x^2+x+1)-((2*x+1)*(x^2-x+1)))/((x^2+x+1)^2)
1.4/4.3
77;6
(2*x-1)*(x^2+x+1)-(((2*x+1)*(x^2-x+1))/((x^2+x+1)^2))
((2*x-1)*(x^2+x+1)-((2*x+1)*(x^2-x+1)))/((x^2+x+1)^2)
| 40/x=2.1x/21 | | 476=68t | | -7y+14=4y-2 | | 2(5x+8)=3(2x+4) | | 5x^4-4x^5=0.5 | | 180=49+41+(2x-8) | | -7+14=4y-2 | | 1=-2/3x | | 3/4c=111/2 | | (13b-2)-4(3b+3)=3 | | -5(2-3k)=-65 | | 4x+12=-2x-20 | | 5(3y-2)=-31 | | 6x^2+7=19 | | 9/2y=5/4 | | 6(x+4)=x-6 | | 2x(4x-6)=180 | | 12-x/2=-4 | | 4x+16+2x=24 | | F(23)=14x+5 | | -7x+9=7x+6 | | 2x-6/x=x-2/4 | | 33=k(88) | | 0=14x+5x+6 | | 180=4x+5x+45 | | -7x+3y-12=0 | | 3/4(6y-3)=-1 | | 2x/15=30 | | 3x-1=2(2x+3)+5 | | (n+2)(n-4)=0 | | 4/3(6y-3)=-1 | | t^3+t^2-5t+3=0 |