12p2+13p=14

Solution for 12p2+13p=14 equation:

12p^2+13p=14

We move all terms to the left:

12p^2+13p-(14)=0

a = 12; b = 13; c = -14;
Δ = b2-4ac
Δ = 132-4·12·(-14)
Δ = 841
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{841}=29$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(13)-29}{2*12}=\frac{-42}{24}
=-1+3/4
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(13)+29}{2*12}=\frac{16}{24}
=2/3
$