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12p^2-57p+63=0
a = 12; b = -57; c = +63;
Δ = b2-4ac
Δ = -572-4·12·63
Δ = 225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{225}=15$$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-57)-15}{2*12}=\frac{42}{24} =1+3/4 $$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-57)+15}{2*12}=\frac{72}{24} =3 $
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