12p2=-8-28p

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Solution for 12p2=-8-28p equation:



12p^2=-8-28p
We move all terms to the left:
12p^2-(-8-28p)=0
We add all the numbers together, and all the variables
12p^2-(-28p-8)=0
We get rid of parentheses
12p^2+28p+8=0
a = 12; b = 28; c = +8;
Δ = b2-4ac
Δ = 282-4·12·8
Δ = 400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{400}=20$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(28)-20}{2*12}=\frac{-48}{24} =-2 $
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(28)+20}{2*12}=\frac{-8}{24} =-1/3 $

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