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12q+2=6(2q+)
We move all terms to the left:
12q+2-(6(2q+))=0
We add all the numbers together, and all the variables
12q-(6(+2q))+2=0
We calculate terms in parentheses: -(6(+2q)), so:We add all the numbers together, and all the variables
6(+2q)
We multiply parentheses
12q
Back to the equation:
-(12q)
2!=0
There is no solution for this equation
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