12q-5(2q-4)=3(q+4)+q

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Solution for 12q-5(2q-4)=3(q+4)+q equation: 



12q-5(2q-4)=3(q+4)+q

We move all terms to the left:

12q-5(2q-4)-(3(q+4)+q)=0

We multiply parentheses

12q-10q-(3(q+4)+q)+20=0



We calculate terms in parentheses: -(3(q+4)+q), so:

3(q+4)+q

We add all the numbers together, and all the variables

q+3(q+4)

We multiply parentheses

q+3q+12

We add all the numbers together, and all the variables

4q+12

Back to the equation:

-(4q+12)



We add all the numbers together, and all the variables

2q-(4q+12)+20=0

We get rid of parentheses

2q-4q-12+20=0

We add all the numbers together, and all the variables

-2q+8=0

We move all terms containing q to the left, all other terms to the right

-2q=-8

q=-8/-2

q=+4

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