12r-(3r+2)=-7(r+6)

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Solution for 12r-(3r+2)=-7(r+6) equation:



12r-(3r+2)=-7(r+6)
We move all terms to the left:
12r-(3r+2)-(-7(r+6))=0
We get rid of parentheses
12r-3r-(-7(r+6))-2=0
We calculate terms in parentheses: -(-7(r+6)), so:
-7(r+6)
We multiply parentheses
-7r-42
Back to the equation:
-(-7r-42)
We add all the numbers together, and all the variables
9r-(-7r-42)-2=0
We get rid of parentheses
9r+7r+42-2=0
We add all the numbers together, and all the variables
16r+40=0
We move all terms containing r to the left, all other terms to the right
16r=-40
r=-40/16
r=-2+1/2

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