12r-3(r+5)=4(3r-6)-3

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Solution for 12r-3(r+5)=4(3r-6)-3 equation: 



12r-3(r+5)=4(3r-6)-3

We move all terms to the left:

12r-3(r+5)-(4(3r-6)-3)=0

We multiply parentheses

12r-3r-(4(3r-6)-3)-15=0



We calculate terms in parentheses: -(4(3r-6)-3), so:

4(3r-6)-3

We multiply parentheses

12r-24-3

We add all the numbers together, and all the variables

12r-27

Back to the equation:

-(12r-27)



We add all the numbers together, and all the variables

9r-(12r-27)-15=0

We get rid of parentheses

9r-12r+27-15=0

We add all the numbers together, and all the variables

-3r+12=0

We move all terms containing r to the left, all other terms to the right

-3r=-12

r=-12/-3

r=+4

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