12s2+18s-30=0

Solution for 12s2+18s-30=0 equation:

12s^2+18s-30=0

a = 12; b = 18; c = -30;
Δ = b2-4ac
Δ = 182-4·12·(-30)
Δ = 1764
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1764}=42$
$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(18)-42}{2*12}=\frac{-60}{24}
=-2+1/2
$
$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(18)+42}{2*12}=\frac{24}{24}
=1
$