12t(-t+10)=0

Solution for 12t(-t+10)=0 equation:

12t(-t+10)=0

We add all the numbers together, and all the variables

12t(-1t+10)=0

We multiply parentheses

-12t^2+120t=0

a = -12; b = 120; c = 0;
Δ = b2-4ac
Δ = 1202-4·(-12)·0
Δ = 14400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{14400}=120$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(120)-120}{2*-12}=\frac{-240}{-24}
=+10
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(120)+120}{2*-12}=\frac{0}{-24}
=0
$