12t(4t+10)=1/4(16+32t)

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Solution for 12t(4t+10)=1/4(16+32t) equation:



12t(4t+10)=1/4(16+32t)
We move all terms to the left:
12t(4t+10)-(1/4(16+32t))=0
Domain of the equation: 4(16+32t))!=0
t∈R
We add all the numbers together, and all the variables
12t(4t+10)-(1/4(32t+16))=0
We multiply parentheses
48t^2+120t-(1/4(32t+16))=0
We multiply all the terms by the denominator
48t^2*4(32t+16))+120t*4(32t+16))-(1=0
We add all the numbers together, and all the variables
48t^2*4(32t+16))+120t*4(32t=0
Wy multiply elements
768t^4(3=0
We do not support etpression: t^4(3

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