12v+3b+9u-3(3v+4u)=

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Solution for 12v+3b+9u-3(3v+4u)= equation:


Simplifying
12v + 3b + 9u + -3(3v + 4u) = 0

Reorder the terms:
12v + 3b + 9u + -3(4u + 3v) = 0
12v + 3b + 9u + (4u * -3 + 3v * -3) = 0
12v + 3b + 9u + (-12u + -9v) = 0

Reorder the terms:
3b + 9u + -12u + 12v + -9v = 0

Combine like terms: 9u + -12u = -3u
3b + -3u + 12v + -9v = 0

Combine like terms: 12v + -9v = 3v
3b + -3u + 3v = 0

Solving
3b + -3u + 3v = 0

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '3u' to each side of the equation.
3b + -3u + 3u + 3v = 0 + 3u

Combine like terms: -3u + 3u = 0
3b + 0 + 3v = 0 + 3u
3b + 3v = 0 + 3u
Remove the zero:
3b + 3v = 3u

Add '-3v' to each side of the equation.
3b + 3v + -3v = 3u + -3v

Combine like terms: 3v + -3v = 0
3b + 0 = 3u + -3v
3b = 3u + -3v

Divide each side by '3'.
b = u + -1v

Simplifying
b = u + -1v

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