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12x(2)=96
We move all terms to the left:
12x(2)-(96)=0
We add all the numbers together, and all the variables
12x^2-96=0
a = 12; b = 0; c = -96;
Δ = b2-4ac
Δ = 02-4·12·(-96)
Δ = 4608
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{4608}=\sqrt{2304*2}=\sqrt{2304}*\sqrt{2}=48\sqrt{2}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-48\sqrt{2}}{2*12}=\frac{0-48\sqrt{2}}{24} =-\frac{48\sqrt{2}}{24} =-2\sqrt{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+48\sqrt{2}}{2*12}=\frac{0+48\sqrt{2}}{24} =\frac{48\sqrt{2}}{24} =2\sqrt{2} $
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