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12x(2)=x+60
We move all terms to the left:
12x(2)-(x+60)=0
We add all the numbers together, and all the variables
12x^2-(x+60)=0
We get rid of parentheses
12x^2-x-60=0
We add all the numbers together, and all the variables
12x^2-1x-60=0
a = 12; b = -1; c = -60;
Δ = b2-4ac
Δ = -12-4·12·(-60)
Δ = 2881
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-\sqrt{2881}}{2*12}=\frac{1-\sqrt{2881}}{24} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+\sqrt{2881}}{2*12}=\frac{1+\sqrt{2881}}{24} $
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