12x(4-3)=4(6x+4)-4

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Solution for 12x(4-3)=4(6x+4)-4 equation: 



12x(4-3)=4(6x+4)-4

We move all terms to the left:

12x(4-3)-(4(6x+4)-4)=0

We add all the numbers together, and all the variables

12x1-(4(6x+4)-4)=0

We add all the numbers together, and all the variables

12x-(4(6x+4)-4)=0



We calculate terms in parentheses: -(4(6x+4)-4), so:

4(6x+4)-4

We multiply parentheses

24x+16-4

We add all the numbers together, and all the variables

24x+12

Back to the equation:

-(24x+12)



We get rid of parentheses

12x-24x-12=0

We add all the numbers together, and all the variables

-12x-12=0

We move all terms containing x to the left, all other terms to the right

-12x=12

x=12/-12

x=-1

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