12x(5x-2)+6=-29-3(x-7)

Solution for 12x(5x-2)+6=-29-3(x-7) equation:

12x(5x-2)+6=-29-3(x-7)

We move all terms to the left:

12x(5x-2)+6-(-29-3(x-7))=0

We multiply parentheses

60x^2-24x-(-29-3(x-7))+6=0


We calculate terms in parentheses: -(-29-3(x-7)), so:

-29-3(x-7)

determiningTheFunctionDomain
-3(x-7)-29

We multiply parentheses

-3x+21-29

We add all the numbers together, and all the variables

-3x-8

Back to the equation:

-(-3x-8)


We get rid of parentheses

60x^2-24x+3x+8+6=0

We add all the numbers together, and all the variables

60x^2-21x+14=0

a = 60; b = -21; c = +14;
Δ = b2-4ac
Δ = -212-4·60·14
Δ = -2919
Delta is less than zero, so there is no solution for the equation