12x*x-6x-18=-18

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Solution for 12x*x-6x-18=-18 equation:



12x*x-6x-18=-18
We move all terms to the left:
12x*x-6x-18-(-18)=0
We add all the numbers together, and all the variables
-6x+12x*x=0
Wy multiply elements
12x^2-6x=0
a = 12; b = -6; c = 0;
Δ = b2-4ac
Δ = -62-4·12·0
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{36}=6$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-6}{2*12}=\frac{0}{24} =0 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+6}{2*12}=\frac{12}{24} =1/2 $

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