12x+(3x+4)+(2x+3)=41

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Solution for 12x+(3x+4)+(2x+3)=41 equation:


Simplifying
12x + (3x + 4) + (2x + 3) = 41

Reorder the terms:
12x + (4 + 3x) + (2x + 3) = 41

Remove parenthesis around (4 + 3x)
12x + 4 + 3x + (2x + 3) = 41

Reorder the terms:
12x + 4 + 3x + (3 + 2x) = 41

Remove parenthesis around (3 + 2x)
12x + 4 + 3x + 3 + 2x = 41

Reorder the terms:
4 + 3 + 12x + 3x + 2x = 41

Combine like terms: 4 + 3 = 7
7 + 12x + 3x + 2x = 41

Combine like terms: 12x + 3x = 15x
7 + 15x + 2x = 41

Combine like terms: 15x + 2x = 17x
7 + 17x = 41

Solving
7 + 17x = 41

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-7' to each side of the equation.
7 + -7 + 17x = 41 + -7

Combine like terms: 7 + -7 = 0
0 + 17x = 41 + -7
17x = 41 + -7

Combine like terms: 41 + -7 = 34
17x = 34

Divide each side by '17'.
x = 2

Simplifying
x = 2

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