12x+(4x-3)=60-(4x+3)

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Solution for 12x+(4x-3)=60-(4x+3) equation: 



12x+(4x-3)=60-(4x+3)

We move all terms to the left:

12x+(4x-3)-(60-(4x+3))=0

We get rid of parentheses

12x+4x-(60-(4x+3))-3=0



We calculate terms in parentheses: -(60-(4x+3)), so:

60-(4x+3)

determiningTheFunctionDomain
-(4x+3)+60

We get rid of parentheses

-4x-3+60

We add all the numbers together, and all the variables

-4x+57

Back to the equation:

-(-4x+57)



We add all the numbers together, and all the variables

16x-(-4x+57)-3=0

We get rid of parentheses

16x+4x-57-3=0

We add all the numbers together, and all the variables

20x-60=0

We move all terms containing x to the left, all other terms to the right

20x=60

x=60/20

x=3

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