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12x+1/5x=9
We move all terms to the left:
12x+1/5x-(9)=0
Domain of the equation: 5x!=0We multiply all the terms by the denominator
x!=0/5
x!=0
x∈R
12x*5x-9*5x+1=0
Wy multiply elements
60x^2-45x+1=0
a = 60; b = -45; c = +1;
Δ = b2-4ac
Δ = -452-4·60·1
Δ = 1785
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-45)-\sqrt{1785}}{2*60}=\frac{45-\sqrt{1785}}{120} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-45)+\sqrt{1785}}{2*60}=\frac{45+\sqrt{1785}}{120} $
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