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12x+12(x+5)=2x(x+5)
We move all terms to the left:
12x+12(x+5)-(2x(x+5))=0
We multiply parentheses
12x+12x-(2x(x+5))+60=0
We calculate terms in parentheses: -(2x(x+5)), so:We add all the numbers together, and all the variables
2x(x+5)
We multiply parentheses
2x^2+10x
Back to the equation:
-(2x^2+10x)
24x-(2x^2+10x)+60=0
We get rid of parentheses
-2x^2+24x-10x+60=0
We add all the numbers together, and all the variables
-2x^2+14x+60=0
a = -2; b = 14; c = +60;
Δ = b2-4ac
Δ = 142-4·(-2)·60
Δ = 676
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{676}=26$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(14)-26}{2*-2}=\frac{-40}{-4} =+10 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(14)+26}{2*-2}=\frac{12}{-4} =-3 $
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