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12x+3=16x-(4x+3)
We move all terms to the left:
12x+3-(16x-(4x+3))=0
We calculate terms in parentheses: -(16x-(4x+3)), so:We get rid of parentheses
16x-(4x+3)
We get rid of parentheses
16x-4x-3
We add all the numbers together, and all the variables
12x-3
Back to the equation:
-(12x-3)
12x-12x+3+3=0
We add all the numbers together, and all the variables
6!=0
There is no solution for this equation
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