12x+3x+8-2=6(x+2)+8

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Solution for 12x+3x+8-2=6(x+2)+8 equation: 



12x+3x+8-2=6(x+2)+8

We move all terms to the left:

12x+3x+8-2-(6(x+2)+8)=0

We add all the numbers together, and all the variables

15x-(6(x+2)+8)+6=0



We calculate terms in parentheses: -(6(x+2)+8), so:

6(x+2)+8

We multiply parentheses

6x+12+8

We add all the numbers together, and all the variables

6x+20

Back to the equation:

-(6x+20)



We get rid of parentheses

15x-6x-20+6=0

We add all the numbers together, and all the variables

9x-14=0

We move all terms containing x to the left, all other terms to the right

9x=14

x=14/9

x=1+5/9

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