12x+4(4x-3)=4(6x+4)-4

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Solution for 12x+4(4x-3)=4(6x+4)-4 equation: 



12x+4(4x-3)=4(6x+4)-4

We move all terms to the left:

12x+4(4x-3)-(4(6x+4)-4)=0

We multiply parentheses

12x+16x-(4(6x+4)-4)-12=0



We calculate terms in parentheses: -(4(6x+4)-4), so:

4(6x+4)-4

We multiply parentheses

24x+16-4

We add all the numbers together, and all the variables

24x+12

Back to the equation:

-(24x+12)



We add all the numbers together, and all the variables

28x-(24x+12)-12=0

We get rid of parentheses

28x-24x-12-12=0

We add all the numbers together, and all the variables

4x-24=0

We move all terms containing x to the left, all other terms to the right

4x=24

x=24/4

x=6

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